We will suppose that particle a is the projectile and b is the target. If we measure the 4-momentum of outgoing particle c, then we know what the 4-momentum of Y is using the energy-momentum conservation laws. We define new variables to indicate the 4 momentum transfer in the process.
Elastic Scattering
Consider the case of elastic scattering, a = c, and the target b is
stationary, then,
Scattering from Constituents
Consider this case then. We imagine that the target consists of two
pieces, that is, it has substructure. The incident particle, a, scatters
off component 1, where we assume that the whole 4 momentum lost by
a is transferred to particle 1.
We can expand the equation for the energy transfer to arrive at
The condition where x is approximately 1 is called quasi-elastic scattering.
In this kinematical condition particle a loses energy and suffers a 3-momentum
change consistent with scattering off an object with the mass of constituent
1. In the case of electrons scattering off a nucleus a broad peak appears
at approximately x = 1 when we set mass 1 equal to the proton mass( then
the x value is the Bjorken x).
If we only measure the scattered electron energy, then the measurement is called an inclusive experiment. These are also called "single-arm" measurements. If we measure the scattered electron in coincidence with another particle, say mass 1, then we call the measurement "exclusive". Exclusive experiments are necessarily coincidence experiments.
If the spectrum of high energy electrons scattered off the proton is measured and we plot the number scattered as a function of the Bjorken x variable we obtain a result similar to that seen below. A broad peak appears at x-Bjorken of about 1/3. If we interpret this bump as due to elastic scattering then we would have to assume that the electrons are elastically scattering off constituents of the proton of mass about 1/3 the proton mass. That is, if we had used 1/3 the proton mass for the mass 1 constituent then the bump would appear at x = 1. The quasi-elastic scattering on the quarks produces a broad spectrum for the same reason that the quasi-elastic scattering on protons in the nucleus produces a broad spectrum. Namely, the constituents receiving the 4-momentum transfer are in motion.
So generally speaking if we plot the scattered electron energy, for
any sort of target we can conclude that the different values of the Bjorken
x correspond to different masses of the constituents absorbing the transferred
4-momentum:
xB < 1 means scattering on a constituent less massive than the proton
xB = 1 means scattering on a constituent about as massive as the proton
xB > 1 means scattering
on a constituent more massive than the proton, such as a correlated
pair of nucleons.
If we see a peak in the spectrum of N(xB
) vs xB at a location x'B , then a kinematical
interpretation of the peak is that electrons are scattering off a constituent
with a mass m1 = x'B . mp
.
Missing momentum and missing energy
In an exclusive reaction ( a coincidence measurement such as A(e,e'p)B
) we measure the energy of the scattered electron and this tells us the
4-momentum absorbed by the target. In addition we also measure the 4-momentum
of one of the particles ejected from the target. The missing momentum is
simply the momentum we did not explicitly measure. We know what it
is, of course, because we have conservation of 4-momentum. The same argument
applies to the missing energy.
In the simple minded picture we have of scattering from a single constituent ( the impulse approximation) the missing momentum of the undetected fragment (x = 2 in our diagram above) is the negative of the momentum our detected proton had in the nucleus before it absorbed the transferred 4-momentum from the electron.
Parallel and Perpendicular Kinematics
If we detect the proton knocked out of the nucleus along the direction
of the 3-momentum transfer, we refer to this as parallel kinematics. The
definition of perpendicular kinematics is not so sharply made. Basically,
perpendicular kinematics is not parallel kinematics. It is not required
that the proton be detected at 90 degrees to the three momentum transfer.
In parallel kinematics we can separate the longitudinal and transverse
resopnse functions. In perpendicular kinematics we determine the longitudinal-transverse
interference response function.